Hilfe?

Answer 1

[ano78577]

7.1)

s(5) = 5^3 - 9 * 5² + 27 * 5

7.2)

s'(t) = 3t² - 18t + 27

s'(1,5) = 3 * 1,5² - 18 * 1,5 + 27 = 6,75

7.3)

s'(t) = 20

3t² - 18t + 27 = 20 |-20

3t² - 18t + 7 = 0 | :3

t² - 6t + 7/3 = 0

PQ Formel

t1,2 = 6/2 +- Wurzel(6² / 4 - 7/3) =

t2 = 3 + Wurzel(36 / 4 - 7/3) =

t2 = 3 + Wurzel(9 - 7/3) =

Comments

[Whme4]

Dankeschön!🍀