Wie rechne ich das ? ?

Answer 1

[nobytree2]

(x- 2)² = (x - 2) * (x - 2)

x² - 4 = (x - 2) * (x + 2)

2 + x = x + 2

also

$\frac{1}{2+x}-\frac{1}{\left(x-2\right)^2}+\frac{1}{x^2-4}=\frac{1}{x+2}-\frac{1}{\left(x-2\right)\left(x-2\right)}+\frac{1}{\left(x-2\right)\left(x+2\right)}$

$=\frac{\left(x-2\right)^2}{\left(x+2\right)\left(x-2\right)^2}-\frac{x+2}{\left(x+2\right)\left(x-2\right)^2}+\frac{x-2}{\left(x+2\right)\left(x-2\right)^2}$ $=\frac{x^2-4x+4-\left(x+2\right)+x-2}{\left(x+2\right)\left(x-2\right)^2}=\frac{x^2-4x}{\left(x+2\right)\left(x-2\right)^2}=\frac{x\left(x-4\right)}{\left(x+2\right)\left(x-2\right)^2}$

Answer 2

[Bargeldnutzer]

die brüche erweitern

mit 3. bionischen! formel

Comments

[Oixibicodex]

Aber wie genau